document.write( "Question 1177997: P(n,n-1)=6
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Algebra.Com's Answer #807164 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "By definition, P(n,n)=n!

\n" ); document.write( "P(3,3) = 3*2*1 = 3!
\n" ); document.write( "P(5,5) = 5*4*3*2*1 = 5!
\n" ); document.write( "etc...

\n" ); document.write( "What about P(n,n-1)?

\n" ); document.write( "P(3,2) = 3*2 = 6 = 3!
\n" ); document.write( "P(5,4) = 5*4*3*2 = 120 = 5!
\n" ); document.write( "etc...

\n" ); document.write( "The only difference between P(n,n-1) and P(n,n) is an additional factor of 1, which of course doesn't change the result.

\n" ); document.write( "So P(n,n-1) = n!

\n" ); document.write( "Then your problem is to solve

\n" ); document.write( "P(n,n-1) = 6 = n!

\n" ); document.write( "By inspection, n = 3.

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