document.write( "Question 1177992: CNNBC recently reported that the mean annual cost of auto insurance is 1002 dollars. Assume the standard deviation is 278 dollars. You take a simple random sample of 76 auto insurance policies.\r
\n" ); document.write( "\n" ); document.write( "Find the probability that a single randomly selected value is less than 981 dollars.
\n" ); document.write( "P(X < 981) = \r
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\n" ); document.write( "\n" ); document.write( "Find the probability that a sample of size
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\n" ); document.write( " is randomly selected with a mean less than 981 dollars.
\n" ); document.write( "P(M < 981) = \r
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\n" ); document.write( "\n" ); document.write( "Enter your answers as numbers accurate to 4 decimal places.
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Algebra.Com's Answer #807159 by Boreal(15235)\"\" \"About 
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P(x<981); z=(x-mean)/sd; 981-1002=-21
\n" ); document.write( "z < -21/278=-0.0755
\n" ); document.write( "probability is 0.4699
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\n" ); document.write( "sample mean <981 is z=(x bar-mean)/sigma/sqrt(n)
\n" ); document.write( "z < (-21)/278/sqrt(76)
\n" ); document.write( "=(-21/278)*(sqrt(76)/278=-0.6585
\n" ); document.write( "probability z < -0.6585=0.2551\r
\n" ); document.write( "\n" ); document.write( "Much less likely that the mean of a sample of 76 will be as small as 981 or less.
\n" ); document.write( "The fourth decimal place will change depending on the rules given for rounding z. If to two places, it will be different from the values here.
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