document.write( "Question 16507: The general manager of Frozenaire Refrigerator Company determines that on Monday it cost the company a total of $25,000 to build 30 refrigerators and on Tuesday it cost $30,000 to build 40 refrigerators. Determine for him the company's daily fixed costs and their marginal cost (that is, the cost to build one refrigerator). \n" ); document.write( "
Algebra.Com's Answer #8071 by foleysdad(7)\"\" \"About 
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We are trying to find two answers here. The cost per refrigerator and the overhead cost of the factory per day.\r
\n" ); document.write( "\n" ); document.write( "Let's assume the following variables:
\n" ); document.write( "r = cost per refrigerator
\n" ); document.write( "f = fixed costs (or overhead) per day for the factory\r
\n" ); document.write( "\n" ); document.write( "Monday is 30r + f = 25000
\n" ); document.write( "Tuesday is 40r + f = 30000\r
\n" ); document.write( "\n" ); document.write( "Lets solve for f using Monday
\n" ); document.write( "f= 25000 -30r
\n" ); document.write( "Now that we know what f is in terms of r let's put it into Tuesday's equation.\r
\n" ); document.write( "\n" ); document.write( "40r + (25000 - 30r) = 30000
\n" ); document.write( "40r -30r + 25000 = 30000
\n" ); document.write( "10r + 25000 = 30000
\n" ); document.write( "10r = 5000
\n" ); document.write( "r = 500\r
\n" ); document.write( "\n" ); document.write( "Plug r into either equation.\r
\n" ); document.write( "\n" ); document.write( "30(500) + f = 25000
\n" ); document.write( "15000 + f = 25000
\n" ); document.write( "f = 10000\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "40(500) + f = 30000
\n" ); document.write( "20000 + f = 30000
\n" ); document.write( "f = 10000\r
\n" ); document.write( "\n" ); document.write( "The answers are :
\n" ); document.write( "f (overhead) = 10,000 per day
\n" ); document.write( "r (cost per refrigerator) = 500 per unit
\n" ); document.write( "
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