document.write( "Question 16507: The general manager of Frozenaire Refrigerator Company determines that on Monday it cost the company a total of $25,000 to build 30 refrigerators and on Tuesday it cost $30,000 to build 40 refrigerators. Determine for him the company's daily fixed costs and their marginal cost (that is, the cost to build one refrigerator). \n" ); document.write( "
Algebra.Com's Answer #8071 by foleysdad(7)![]() ![]() ![]() You can put this solution on YOUR website! We are trying to find two answers here. The cost per refrigerator and the overhead cost of the factory per day.\r \n" ); document.write( "\n" ); document.write( "Let's assume the following variables: \n" ); document.write( "r = cost per refrigerator \n" ); document.write( "f = fixed costs (or overhead) per day for the factory\r \n" ); document.write( "\n" ); document.write( "Monday is 30r + f = 25000 \n" ); document.write( "Tuesday is 40r + f = 30000\r \n" ); document.write( "\n" ); document.write( "Lets solve for f using Monday \n" ); document.write( "f= 25000 -30r \n" ); document.write( "Now that we know what f is in terms of r let's put it into Tuesday's equation.\r \n" ); document.write( "\n" ); document.write( "40r + (25000 - 30r) = 30000 \n" ); document.write( "40r -30r + 25000 = 30000 \n" ); document.write( "10r + 25000 = 30000 \n" ); document.write( "10r = 5000 \n" ); document.write( "r = 500\r \n" ); document.write( "\n" ); document.write( "Plug r into either equation.\r \n" ); document.write( "\n" ); document.write( "30(500) + f = 25000 \n" ); document.write( "15000 + f = 25000 \n" ); document.write( "f = 10000\r \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( "\n" ); document.write( "40(500) + f = 30000 \n" ); document.write( "20000 + f = 30000 \n" ); document.write( "f = 10000\r \n" ); document.write( "\n" ); document.write( "The answers are : \n" ); document.write( "f (overhead) = 10,000 per day \n" ); document.write( "r (cost per refrigerator) = 500 per unit \n" ); document.write( " |