document.write( "Question 1177912: Mark is two years older than Buddy. In a year from now Mark will be twice as old as Buddy. Find their present ages.\r
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Algebra.Com's Answer #807051 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "Buddy is \"x\" years old
\n" ); document.write( "Mark is two years older than Buddy,\"x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( " In a year from now Mark will be twice as old as Buddy.\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%2B2=2%28x%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B3=2x%2B2\"\r
\n" ); document.write( "\n" ); document.write( "\"3-2=2x-x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=1\"\r
\n" ); document.write( "\n" ); document.write( "Buddy is \"1\" year old and Mark is \"3\" year old now\r
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