document.write( "Question 1177882: The amount of time spent by adults playing sports per day is normally distributed with a mean 4 hours and standard deviation of 1.25 hours.\r
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document.write( "1. Find the probability that a randomly selected adult plays sports between 5 and 5.5 hours per day. \r
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document.write( "2.Find the third quartile of the distribution of time an adult spend in playing sports.\r
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document.write( "3.Find the probability that if four adults are randomly selected, their average number of hours spent playing sports is more than 5 hours per day \n" );
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Algebra.Com's Answer #807044 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "between 5 and 5.5 hours is a z between 1/1.25 or 0.8 and a z of 1.5/1.25=1.2 \n" ); document.write( "that probability for a z is 0.0968 \n" ); document.write( "- \n" ); document.write( "third quartile-find z for 0.75 probability, and that is +0.6745 \n" ); document.write( "0.6745=(x-4)/1.25 \n" ); document.write( "so x=4.84 hours at the third quartile \n" ); document.write( "- \n" ); document.write( "this is a z>(5-4)/1.25/sqrt(4) \n" ); document.write( ">1*2/1.25 \n" ); document.write( "z>1.6 \n" ); document.write( "probability=0.0548\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |