document.write( "Question 1177877: Mary is twice as old as Hilda. Four years from now the sum of their ages will be 41. Find their present age.
\n" ); document.write( "(side-note, I'm in grade 9 so my teacher expects me to use only ONE variable)
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Algebra.Com's Answer #807006 by mananth(16946)\"\" \"About 
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Mary is twice as old as Hilda. Four years from now the sum of their ages will be 41. Find their present age.
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\n" ); document.write( "Let Hilda's age be x\r
\n" ); document.write( "\n" ); document.write( "Mary's age will be 2x\r
\n" ); document.write( "\n" ); document.write( "2x+4 +x+4 = 41\r
\n" ); document.write( "\n" ); document.write( "3x+8 =41\r
\n" ); document.write( "\n" ); document.write( "3x=41-8\r
\n" ); document.write( "\n" ); document.write( "3x =33
\n" ); document.write( "x=11
\n" ); document.write( "Hilda's age 11 years
\n" ); document.write( "Mary's age = 2x = 22 years\r
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