document.write( "Question 1177868: A pear costs x cents. An orange costs y cents less than a pear. Find the cost of 4 pears and half a dozen of oranges. \n" ); document.write( "
Algebra.Com's Answer #806998 by amarjeeth123(569)![]() ![]() ![]() You can put this solution on YOUR website! Cost of a pear=x cents \n" ); document.write( "Cost of an orange=(x-y) cents \n" ); document.write( "Cost of 4 pears=4x cents \n" ); document.write( "Half a dozen means 6 oranges \n" ); document.write( "Cost of 6 oranges=6(x-y) cents \n" ); document.write( "Total cost=Cost of 4 pears+Cost of 6 oranges=4x+6(x-y)=4x+6x-6y=10x-6y \n" ); document.write( "Answer=10x-6y cents \n" ); document.write( " |