document.write( "Question 1177868: A pear costs x cents. An orange costs y cents less than a pear. Find the cost of 4 pears and half a dozen of oranges. \n" ); document.write( "
Algebra.Com's Answer #806998 by amarjeeth123(569)\"\" \"About 
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Cost of a pear=x cents
\n" ); document.write( "Cost of an orange=(x-y) cents
\n" ); document.write( "Cost of 4 pears=4x cents
\n" ); document.write( "Half a dozen means 6 oranges
\n" ); document.write( "Cost of 6 oranges=6(x-y) cents
\n" ); document.write( "Total cost=Cost of 4 pears+Cost of 6 oranges=4x+6(x-y)=4x+6x-6y=10x-6y
\n" ); document.write( "Answer=10x-6y cents
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