document.write( "Question 929035: The stopping distance d of a car after the brakes are applied varies directly as the square of the speed r. If a car traveling 20 mph can stop in 20 ft, how many feet will it take the same car to sop when it is traveling 100 mph? \n" ); document.write( "
Algebra.Com's Answer #806961 by greenestamps(13203)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "for tutor @CubeyThePenguin....

\n" ); document.write( "(1) Your cryptic calculations with no explanation are of no use to the student who is trying to learn how to solve the problem.

\n" ); document.write( "(2) I can't tell what the calculations you show are supposed to be doing to solve the problem. Remember, your purpose as a tutor here is not to show that you know how to solve a problem; your purpose is to help the student learn how to solve the problem.

\n" ); document.write( "(3) And in this case, whatever your calculations were supposed to be doing, they gave the wrong answer....

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\n" ); document.write( "Informally, the solution is simple. Since the stopping distance varies directly as the square of the speed, a speed 5 times as great means a stopping distance 5^2=25 times as great. ANSWER: 25(20 feet) = 500 feet.

\n" ); document.write( "More formally....

\n" ); document.write( "\"d+=+kr%5E2\"

\n" ); document.write( "Find the constant of proportionality knowing that the stopping distance is 20 feet at 20mph.

\n" ); document.write( "\"20+=+k%2820%5E2%29\"
\n" ); document.write( "\"20+=+400k\"
\n" ); document.write( "\"k+=+1%2F20\"

\n" ); document.write( "Use that constant to find the sopping distance if the speed is 100mph.

\n" ); document.write( "\"d+=+kr%5E2\"
\n" ); document.write( "\"d+=+%281%2F20%29%28100%5E2%29+=+10000%2F20+=+500\"

\n" ); document.write( "ANSWER: 500 feet

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