document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=929035>Question 929035</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The stopping distance d of a car after the brakes are applied varies directly as the square of the speed r. If a car traveling 20 mph can stop in 20 ft, how many feet will it take the same car to sop when it is traveling 100 mph? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806945 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d:r^2 ---> 20:(20^2) = 100:(x)\r<BR>\n" );
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document.write( "20/400 = 100/x<BR>\n" );
document.write( "1/20 = 100/x\r<BR>\n" );
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document.write( "stopping distance = x = 2000 ft </SPAN>\n" );
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