document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1177814>Question 1177814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> consider the numbers 1,4,5,8,9 and 0. if repetition is not aalowed, how many three-digit numbers can be formed from these numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806936 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Five choices for the hundreds digit {1,4,5,8,9}.<BR>\n" );
document.write( "Five choices for the tens digit {five digits, the four not chosen above, + \"0\"}.<BR>\n" );
document.write( "Four choices for the ones digit {the four remaining digits}.<br>\r<BR>\n" );
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document.write( "5*5*4 = 100<br>\r<BR>\n" );
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document.write( "The above assumes a true 3-digit number (in the purest numerical sense, \"014\" would not be a 3-digit number because it is normally written \"14\").   However, in some applications (keypad lock for example, 014 could be combination).  If leading zero is allowed, you get 6*5*4...\r<BR>\n" );
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document.write( " </SPAN>\n" );
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