document.write( "Question 1177813: A parabolic arch spans a stream 200 feet wide. How high above the stream must the arch be to give a minimum clearance of 40 feet over a channel in the center that is 120 feet wide?
\n" ); document.write( "I have tried setting up various equations, but none have worked so far. Thank you for any help!
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Algebra.Com's Answer #806929 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Let the origin of the coordinate system be the center of the stream at the surface; then the vertex of the parabola is at (0,k). The equation is then of the form

\n" ); document.write( "\"y=ax%5E2%2Bk\"

\n" ); document.write( "where, because the parabola opens downward, we know a is some negative constant.

\n" ); document.write( "We can determine a and k using the information in the problem:

\n" ); document.write( "(1) The arch is 200 feet wide. This means 100 feet either side of the center of the stream the height of the arch is zero:
\n" ); document.write( "\"0+=+a%28100%5E2%29%2Bk\" [1]

\n" ); document.write( "(2) We need a minimum vertical clearance of 40 feet everywhere in a channel 120 feet wide in the center of the stream. That means at 60 feet either side of the center of the stream the height must be 40:
\n" ); document.write( "\"40+=+a%2860%5E2%29%2Bk\" [2]

\n" ); document.write( "Solve the pair of equations [1] and [2].

\n" ); document.write( "\"0+=+10000a%2Bk\"
\n" ); document.write( "\"40+=+3600a%2Bk\"

\n" ); document.write( "Subtract the second equation from the first to eliminate k.

\n" ); document.write( "\"-40+=+6400a\"
\n" ); document.write( "\"a+=+-40%2F6400+=+-1%2F160\"

\n" ); document.write( "Substitute that value in [1] to find k, which is the height of the arch we are to find.

\n" ); document.write( "\"0+=+%28-1%2F160%29%2810000%29%2Bk+=+-62.5%2Bk\"
\n" ); document.write( "\"k+=+62.5\"

\n" ); document.write( "ANSWER: The height of the arch above the stream must be 62.5 feet.

\n" ); document.write( "CHECK: The equation of the parabola is \"y=f%28x%29+=+%28-1%2F160%29x%5E2%2B62.5\".
\n" ); document.write( "\"f%2860%29+=+%28-1%2F160%293600%2B62.5+=+-22.5%2B62.5+=+40\"
\n" ); document.write( "\"f%28100%29+=+%28-1%2F160%2910000%2B62.5+=+-62.5%2B62.5+=+0\"

\n" ); document.write( "A graph, showing a width of 200 feet and a height of 40 feet 60 feet either side of the center of the arch.

\n" ); document.write( "\"graph%28800%2C200%2C-120%2C120%2C-20%2C80%2C%28-1%2F160%29x%5E2%2B62.5%2C40%29\"

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