document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1177805>Question 1177805</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a triangle with side lengths 13, 20, and 21<BR>\n" );
document.write( "is 126 units^2. What would be the area of a triangle<BR>\n" );
document.write( "with side lengths of 130, 200, and 210? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806910 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the base be 21 and the altitude is 12, because A=(1/2)bh<BR>\n" );
document.write( "the second triangle has 10 x the base and 10 x the altitude, so the area will be 100 x as much or 12,600 units ^2.<BR>\n" );
document.write( "Draw a 3-4-5 right triangle.<BR>\n" );
document.write( "The area is 6 units ^2, (1/2)(4*3)<BR>\n" );
document.write( "if the triangle were 30-40-50, the area would be (1/2)(1200)=600 units^2 </SPAN>\n" );
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