document.write( "Question 1177767: A consulting group believes that 70% of the people in a certain county are satisfied with their health coverage. Assuming that this is true, find the probability that in a random sample of
\n" ); document.write( "15 people from the county:
\n" ); document.write( "(a) Exactly 10 are satisfied with their health coverage, and interpret.
\n" ); document.write( "(b) Not more than 10 are satisfied with their health coverage, and interpret.
\n" ); document.write( "(c) What is the expected number of people out of 15 that are satisfied with their health
\n" ); document.write( "coverage?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #806870 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "Hi\r\n" );
document.write( "Binomial Distribution:  p(satisfied with their health coverage) = .7\r\n" );
document.write( "Using TI or similarly an inexpensive calculator like a Casio fx-115 ES plus \r\n" );
document.write( "n = 15\r\n" );
document.write( "(a) P(x = 10) = binompdf(15, .7, 10) = .2061\r\n" );
document.write( "(b) P(x ≤ 10) = binomcdf(15, .7, 10) = .4845\r\n" );
document.write( "(c) Expected = .7 * 15 = 10.5  or 10 (rounded down to whole number)\r\n" );
document.write( "\r\n" );
document.write( "Important You are  comfortable using Your Calculator.\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
document.write( "

\n" ); document.write( " \n" ); document.write( "

\n" );