document.write( "Question 1177723: It takes pump A 2 hours less time than pump B to empty a pool. Pump A is started at 8:00am and pump B at 10:00am. At 12:00pm 60% of the pool.is empty when pump B broke down. How much time after 12:00pm would it take pump A to empty the pool? \n" ); document.write( "
Algebra.Com's Answer #806853 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Let pump B to empty a pool be x hours \n" ); document.write( "It empties 1/x in 1 hour\r \n" ); document.write( "\n" ); document.write( "pump A to empty a pool will be x-2 hours \n" ); document.write( "It empties 1/(x-2) in 1 hour \n" ); document.write( "Pump B runs for two hours and both work for two hours \n" ); document.write( "They empty 40 % of the tank \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "factorise\r \n" ); document.write( "\n" ); document.write( "Pump B takes 11 hours \n" ); document.write( "Pump A takes 9 hours\r \n" ); document.write( "\n" ); document.write( "Pump A has to empty remaining water (3/5) of the tank\r \n" ); document.write( "\n" ); document.write( "Pump A will take 3/5 * 9 = 27/5 = 5.4 hours after 12.00 \n" ); document.write( " |