document.write( "Question 1177723: It takes pump A 2 hours less time than pump B to empty a pool. Pump A is started at 8:00am and pump B at 10:00am. At 12:00pm 60% of the pool.is empty when pump B broke down. How much time after 12:00pm would it take pump A to empty the pool? \n" ); document.write( "
Algebra.Com's Answer #806853 by mananth(16946)\"\" \"About 
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Let pump B to empty a pool be x hours
\n" ); document.write( "It empties 1/x in 1 hour\r
\n" ); document.write( "\n" ); document.write( "pump A to empty a pool will be x-2 hours
\n" ); document.write( "It empties 1/(x-2) in 1 hour
\n" ); document.write( "Pump B runs for two hours and both work for two hours
\n" ); document.write( "They empty 40 % of the tank
\n" ); document.write( "\"2%2Fx+%2B+2%2F%28x-2%29+=2%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"%282x-4+%2B2x%29%2Fx%28x-2%29+=+2%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"5%284x-4%29=2%28x%5E2-2x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"20x+-20+=+2x%5E2-4x\"\r
\n" ); document.write( "\n" ); document.write( "\"2x%5E2-24x%2B20=0\"
\n" ); document.write( "factorise\r
\n" ); document.write( "\n" ); document.write( "Pump B takes 11 hours
\n" ); document.write( "Pump A takes 9 hours\r
\n" ); document.write( "\n" ); document.write( "Pump A has to empty remaining water (3/5) of the tank\r
\n" ); document.write( "\n" ); document.write( "Pump A will take 3/5 * 9 = 27/5 = 5.4 hours after 12.00
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