document.write( "Question 1177730: In triangle ABC, (bsinC)(bcosC + c(cosB)) = 42. What is the area of the triangle? \n" ); document.write( "
Algebra.Com's Answer #806819 by MathLover1(20850)\"\" \"About 
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\"D\" = projection of \"A\" on \"BC\".\r
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\n" ); document.write( "\n" ); document.write( "\"b%2Asin%28C%29+=+AD\" => height of the triangle \"ABC\" with respect to base\"+BC\"\r
\n" ); document.write( "\n" ); document.write( "\"b%2Acos%28C%29+=+DC\" =>projection of side \"b+=+AC\" onto base \"BC\"\r
\n" ); document.write( "\n" ); document.write( "\"c%2Acos%28B%29+=+BD\"=>projection of side \"c+=+AB\" onto base \"BC\"\r
\n" ); document.write( "\n" ); document.write( "Thus \r
\n" ); document.write( "\n" ); document.write( "\"b%2Acos%28C%29%2Bc%2Acos%28B%29+=+BD+%2B+DC+=+BC+=+base\"\r
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\n" ); document.write( "\n" ); document.write( "So \r
\n" ); document.write( "\n" ); document.write( "Therefore the area of \"ABC+=+42%2F2+=+21+\" square units.\r
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