document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1177677>Question 1177677</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to the following sequence how to find the nth term\r<BR>\n" );
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document.write( "1, 2, 3, 6, 11, 20, 37, 68, … </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806781 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "TRIbonacci numbers -- like Fibonacci numbers except each term is the sum of the preceding THREE terms:<BR>\n" );
document.write( "first three numbers 1, 2, 3;<BR>\n" );
document.write( "each subsequent term is the sum of the preceding three terms<br><BR>\n" );
document.write( "1<BR>\n" );
document.write( "2<BR>\n" );
document.write( "3<BR>\n" );
document.write( "1+2+3=6<BR>\n" );
document.write( "2+3+6=11<BR>\n" );
document.write( "3+6+11=20<BR>\n" );
document.write( "6+11+20=37<BR>\n" );
document.write( "11+20+37=68<BR>\n" );
document.write( "...<br><BR>\n" );
document.write( "You can use the recursive definition to find as many terms as you want.<br><BR>\n" );
document.write( "I don't believe there is an explicit formula for the n-th term.<br><BR>\n" );
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