document.write( "Question 1177647: (−7, −7)
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\n" ); document.write( "0 ≤ 𝜃 < 2𝜋.\r
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Algebra.Com's Answer #806764 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi\r\n" );
document.write( "(−7, −7) 3rd quadrant\r\n" );
document.write( " r = sqrt(x^2 + y^2) = sqrt(98) =  ±  7√2\r\n" );
document.write( "for the point for 0 ≤ 𝜃 < 2𝜋\r\n" );
document.write( "tan θ = 1  Look below:  θ is 5π/4 (3rd quadrant)  0r 5π/4 - π = π/4 if r< 0 \r\n" );
document.write( "two sets of polar coordinates: (r,θ) \r\n" );
document.write( "(7√2, 5π/4) and (-7√2, π/4) \r\n" );
document.write( "Wish You the Best in your Studies\r\n" );
document.write( "(cos, sin)  Unit Circle:\r\n" );
document.write( "     .\r\n" );
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