document.write( "Question 1177649: (8 sqrt3, −8)
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Algebra.Com's Answer #806762 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi\r\n" );
document.write( "(8 sqrt3, −8) 4th quadrant\r\n" );
document.write( " r = sqrt(x^2 + y^2) = sqrt(4*64) = ± 16\r\n" );
document.write( "for the point for 0 ≤ 𝜃 < 2𝜋\r\n" );
document.write( "tan θ = x/y = - √3 look below: θ is 11π/6 (4th quadrant)  0r 11π/6 - π = 5π/6 if r<0\r\n" );
document.write( "two sets of polar coordinates:\r\n" );
document.write( "(16, 11π/6)  and (-16, 5π/6) \r\n" );
document.write( "Wish You the Best in your Studies\r\n" );
document.write( "(cos, sin)  Unit Circle:\r\n" );
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