document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1177555>Question 1177555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please I will Cashapp 10$ If anyone can solve it it's due today I really need help.  \r<BR>\n" );
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document.write( "Pick DIFFERENT values that meet each description.\r<BR>\n" );
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document.write( "m = ____ (m is an integer and m<-10)   d = ____ (d is an integer and -10 < d < -1)\r<BR>\n" );
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document.write( "n = ____ (n is an integer and n > 20)  	r = ____ (r is a rational # and 0 < r < 1)\r<BR>\n" );
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document.write( "1) Create an arithmetic sequence with a common difference of d, and the third term in the sequence is m.  Show the first 5 terms of the sequence.\r<BR>\n" );
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document.write( "2) Write the explicit rule for the sequence that you created.  Use your rule to confirm the 5th term of the sequence.\r<BR>\n" );
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document.write( "3) Write the recursive rule for your arithmetic sequence.\r<BR>\n" );
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document.write( "4) Use the formula for arithmetic series, and find the sum of the first 10 terms of the sequence that you created.  \r<BR>\n" );
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document.write( "Part 2:<BR>\n" );
document.write( "1) Using your chosen value of n, create a geometric sequence with a common ratio of r, and the first term of the sequence is n.  Show the first 5 terms of the sequence.\r<BR>\n" );
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document.write( "2) Write the explicit rule for the sequence that you created.  Use your rule to find the 10th term of the sequence.\r<BR>\n" );
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document.write( "3) Write the recursive rule for your geometric sequence.\r<BR>\n" );
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document.write( "4) Write a summation notation that depicts the sum of the first 25 terms of the geometric series.  Find the sum.  (Round to 5 decimal places if necessary.)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806750 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806750\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Arithmetic:<BR>\n" );
document.write( "m is -25 d=-5<BR>\n" );
document.write( "-15,-20,-25,-30,-35<BR>\n" );
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document.write( "this is an=a1+(n-1)d=-15+(n-1)(-5)<BR>\n" );
document.write( "series is 15,-20,-25,-30,-35<BR>\n" );
document.write( "a5=-15+4(-5)=-35<BR>\n" );
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document.write( "an=a(n-1)-5<BR>\n" );
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document.write( "Sn=(n/2)(2a1+(n-1)d)<BR>\n" );
document.write( "S10=5(-30+9(-5))=-375<BR>\n" );
document.write( "series of -15,-20,-25,-30,-35,-40,-45,-50,-55,-60<BR>\n" );
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document.write( "n=625 and r=0.2 or 1/5<BR>\n" );
document.write( "625,125,25,5,1<BR>\n" );
document.write( "rule is a(n)=a(n-1)*(1/5)<BR>\n" );
document.write( "an=ar^(n-1)  so a10=(.2^9)=0.00032, this is also, continuing from above(1/5+(1/25)+(1/125)+(1/625)+(1/3125)), where 1/3125 is the 10th term of the sequence. Note: 1/3125 is 0.00032.<BR>\n" );
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document.write( "summation is S25=(a (1-r^25)/(1-r))<BR>\n" );
document.write( "625(1-.2^25/.8=781.25<BR>\n" );
document.write( "This is the limit of the series, which is a/(1-r)=625/.8=781.25<BR>\n" );
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