document.write( "Question 1177626: The product of three integers is 90. The second number is twice the first number. The third number is two more than the first number. What are the three numbers? Use a polynomial and the calculator to answer the question. \n" ); document.write( "
Algebra.Com's Answer #806728 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "FIRST               n\r\n" );
document.write( "SECOND             2n\r\n" );
document.write( "THIRD              n+2\r\n" );
document.write( "PRODUCT             90\r\n" );
document.write( "

\n" ); document.write( "\"2n%5E2%28n%2B2%29=90\"\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"n%5E2%28n%2B2%29=45\"\r
\n" ); document.write( "\n" ); document.write( "Try looking for factorizations.\r
\n" ); document.write( "\n" ); document.write( "\"3%2A3%2A5=45\"
\n" ); document.write( "\"3%5E2%283%2B2%29=45\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The numbers are 3, 5, 6. \n" ); document.write( "
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