document.write( "Question 1177623: A ball is launched at 19.6 meters per second from a 58.8 meter tall platform. The equation for the object’s height h (in meters) at time t (in seconds) after launch is h(t)=-4.9t^2+19.6t+58.8. How high does the ball fly in the air? When does the ball hit the ground? \n" ); document.write( "
Algebra.Com's Answer #806711 by mananth(16946)\"\" \"About 
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A ball is launched at 19.6 meters per second from a 58.8 meter tall platform. The equation for the object’s height h (in meters) at time t (in seconds) after launch is h(t)=-4.9t^2+19.6t+58.8.\r
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\n" ); document.write( "\n" ); document.write( "h(t)=-4.9t^2+19.6t+58.8.
\n" ); document.write( "t= -b/2a = -19.6/2*(-4.9) =2\r
\n" ); document.write( "\n" ); document.write( "S(2) = 4.9(2^2) +19.6*2 +58.8
\n" ); document.write( "S(2) = 78.4 ft.
\n" ); document.write( "Maximum height = 78.4 ft\r
\n" ); document.write( "\n" ); document.write( "When it hits the ground height is 0\r
\n" ); document.write( "\n" ); document.write( "h(t)=-4.9t^2+19.6t+58.8.\r
\n" ); document.write( "\n" ); document.write( "-4.9t^2+19.6t+58.8 =0
\n" ); document.write( "/4.9\r
\n" ); document.write( "\n" ); document.write( "-t^2 +4t +12=0\r
\n" ); document.write( "\n" ); document.write( "(t-6)(t+2)=0\r
\n" ); document.write( "\n" ); document.write( "t=6 , it hits the ground\r
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