document.write( "Question 1177601: a train travels 30 miles in 5/6 the amount of time it takes a man to drive a car the same distance. if the rate of the train exceeds the rate of the car by 8 miles per hour, find the rate at which the car is traveling. \n" ); document.write( "

Algebra.Com's Answer #806702 by ikleyn(52914) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            Having the solution, as it is written and presented in the post by @josgarithmetic, \r
\n" ); document.write( "\n" ); document.write( "            I feel the need to REWRITE it from the scratch,\r
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\n" ); document.write( "\n" ); document.write( "            since his presentation is below any acceptable level.\r
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document.write( "Let x be the car's rate, in miles per hour.\r\n" );
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document.write( "Then the car's time traveled is    =   hours.\r\n" );
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document.write( "According to the condition, then the train's time traveled is   =  =  =   hours.\r\n" );
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document.write( "Thus the train's rate is   =  = .\r\n" );
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document.write( "We are given  that the difference of rates is 8 miles per hour.  It means\r\n" );
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document.write( "     - x = 8.\r\n" );
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document.write( "To solve this equation, multiply both sides by 5.  You will get\r\n" );
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document.write( "    6x - 5x = 40\r\n" );
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document.write( "       x    = 40.\r\n" );
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document.write( "Thus the rate of the car is 40 miles per hour.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved and presented in a way, as it SHOULD be DONE.\r
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