document.write( "Question 697748: find two consecutive negative integers whose product is 48 more than three times the first integer \n" ); document.write( "
Algebra.Com's Answer #806634 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! consecutive negative integers: x, (x+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x(x+1) = 48 + 3x \n" ); document.write( "x^2 + x = 48 = 3x \n" ); document.write( "x^2 - 2x - 48 = 0 \n" ); document.write( "(x - 8)(x + 6) = 0 \n" ); document.write( "x = 8, x = -6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is negative ---> integers: -6, -5 \n" ); document.write( " |