document.write( "Question 1177527: The sum of the first 10 terms of an arithmetic progression is 80 and the sum of the next 12 terms is 624. What is the arithmetic progression?\r
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Algebra.Com's Answer #806583 by mananth(16946)\"\" \"About 
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The sum of the first 10 terms of an arithmetic progression is 80 and the sum of the next 12 terms is 624. What is the arithmetic progression?\r
\n" ); document.write( "\n" ); document.write( "S10 = 10/2(2a+(10-1)d)\r
\n" ); document.write( "\n" ); document.write( "S10 = 10a+45d =80 ----------------1\r
\n" ); document.write( "\n" ); document.write( "S22 = 22/2(2a+(22-1)d)\r
\n" ); document.write( "\n" ); document.write( "S22 = 11(2a+21d)\r
\n" ); document.write( "\n" ); document.write( "S22= 22a+231d\r
\n" ); document.write( "\n" ); document.write( "S22-S10 =80\r
\n" ); document.write( "\n" ); document.write( "22a+231d-80 =624\r
\n" ); document.write( "\n" ); document.write( "22a +231d = 704
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\n" ); document.write( "2a+21d=64----------------2\r
\n" ); document.write( "\n" ); document.write( "solve equation 1 & 2
\n" ); document.write( "a=-10,d=4\r
\n" ); document.write( "\n" ); document.write( "-10,-6,-2,2,6,...............\r
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