document.write( "Question 1177520: From a tank 1/3 full of water, 21 liters loss due to leaking, 1/2 water remained. Determine capacity of tank.\r
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document.write( "c = capacity\r
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document.write( "1/3c - 21 = .5c\r
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document.write( ".66c - 21 = .5c\r
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document.write( "Not sure if correct steps.\r
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Algebra.Com's Answer #806569 by josgarithmetic(39630) ![]() You can put this solution on YOUR website! Unsure your description; maybe rewrite it so nothing is unclear/ambiguous/imprecise.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------- \n" ); document.write( "From a tank 1/3 full of water, 21 liters loss due to leaking, 1/2 water remained. Determine capacity of tank. \n" ); document.write( "--------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c, the capacity \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "\"Half the water remained\" - Is that, half of the initial amount of water remained? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---- \n" ); document.write( "----\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Based on the private message, solving the above equation will also show capacity was 126 liters. \n" ); document.write( " |