document.write( "Question 1177520: From a tank 1/3 full of water, 21 liters loss due to leaking, 1/2 water remained. Determine capacity of tank.\r
\n" ); document.write( "\n" ); document.write( "c = capacity\r
\n" ); document.write( "\n" ); document.write( "1/3c - 21 = .5c\r
\n" ); document.write( "\n" ); document.write( ".66c - 21 = .5c\r
\n" ); document.write( "\n" ); document.write( "Not sure if correct steps.\r
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Algebra.Com's Answer #806569 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
Unsure your description; maybe rewrite it so nothing is unclear/ambiguous/imprecise.\r
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\n" ); document.write( "From a tank 1/3 full of water, 21 liters loss due to leaking, 1/2 water remained. Determine capacity of tank.
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\n" ); document.write( "\n" ); document.write( "c, the capacity
\n" ); document.write( "\"c%2F3\" liters to begin\r
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\n" ); document.write( "\n" ); document.write( "\"c%2F3-21\", liters in tank due to leakage\r
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\n" ); document.write( "\n" ); document.write( "\"Half the water remained\" - Is that, half of the initial amount of water remained?
\n" ); document.write( "\"c%2F3-21=%281%2F2%29%28c%2F3%29\"----------this would seem to represent that description. Simplify and solve for c.\r
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\n" ); document.write( "\n" ); document.write( "Based on the private message, solving the above equation will also show capacity was 126 liters.
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