document.write( "Question 110680: y=1/3x + 2/3
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Algebra.Com's Answer #80656 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"y=1%2F3x+%2B+2%2F3\"\r
\n" ); document.write( "\n" ); document.write( "\"y=5%2F7x%962\"\r
\n" ); document.write( "\n" ); document.write( "In standard form:\r
\n" ); document.write( "\n" ); document.write( "\"-%281%2F3%29x+%2B+y=+2%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"-%285%2F7%29x+%2B+y=+-2\"\r
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition
TEST
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\n" ); document.write( " \"%28%28-1%2F3%29%29%2Ax%2B%281%29%2Ay=%282%2F3%29\" Start with the first equation
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\n" ); document.write( " \"3%28%28%28-1%2F3%29%29%2Ax%2B%281%29%2Ay%29=%283%29%2A%28%282%2F3%29%29\" Multiply both sides by the LCD 3
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\n" ); document.write( " \"-1%2Ax%2B3%2Ay=2\"Distribute and simplify
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\n" ); document.write( " \"%28%28-5%2F7%29%29%2Ax%2B%281%29%2Ay=%28-2%29\" Start with the second equation
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\n" ); document.write( " \"7%28%28%28-5%2F7%29%29%2Ax%2B%281%29%2Ay%29=%287%29%2A%28%28-2%29%29\" Multiply both sides by the LCD 7
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\n" ); document.write( " \"-5%2Ax%2B7%2Ay=0\" Distribute and simplify
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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"-1%2Ax%2B3%2Ay=2\"
\n" ); document.write( " \"-5%2Ax%2B7%2Ay=0\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get -1 and -5 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of -1 and -5 is 5, we need to multiply both sides of the top equation by -5 and multiply both sides of the bottom equation by 1 like this:
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\n" ); document.write( " \"-5%2A%28-1%2Ax%2B3%2Ay%29=%282%29%2A-5\" Multiply the top equation (both sides) by -5
\n" ); document.write( " \"1%2A%28-5%2Ax%2B7%2Ay%29=%280%29%2A1\" Multiply the bottom equation (both sides) by 1
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"5%2Ax-15%2Ay=-10\"
\n" ); document.write( " \"-5%2Ax%2B7%2Ay=0\"
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\n" ); document.write( " Notice how 5 and -5 add to zero (ie \"5%2B-5=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%285%2Ax-5%2Ax%29-15%2Ay%2B7%2Ay%29=-10%2B0\"
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\n" ); document.write( " \"%285-5%29%2Ax-15%2B7%29y=-10%2B0\"
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\n" ); document.write( " \"cross%285%2B-5%29%2Ax%2B%28-15%2B7%29%2Ay=-10%2B0\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-8%2Ay=-10\"
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\n" ); document.write( " \"y=-10%2F-8\" Divide both sides by \"-8\" to solve for y
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\n" ); document.write( " \"y=5%2F4\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"-1%2Ax%2B3%2Ay=2\" to solve for x
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\n" ); document.write( " \"-1%2Ax%2B3%285%2F4%29=2\" Plug in \"y=5%2F4\"
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\n" ); document.write( " \"-1%2Ax%2B15%2F4=2\" Multiply
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\n" ); document.write( " \"-1%2Ax%2B15%2F4=2\" Reduce
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\n" ); document.write( " \"-1%2Ax=2-15%2F4\" Subtract \"15%2F4\" from both sides
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\n" ); document.write( " \"-1%2Ax=8%2F4-15%2F4\" Make 2 into a fraction with a denominator of 4
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\n" ); document.write( " \"-1%2Ax=-7%2F4\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F-1%29%28-1%29%29%2Ax=%28-7%2F4%29%281%2F-1%29\" Multiply both sides by \"1%2F-1\". This will cancel out \"-1\" on the left side.
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\n" ); document.write( " \"x=7%2F4\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=7%2F4\", \"y=5%2F4\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"7%2F4\", \"5%2F4\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"-1%2Ax%2B3%2Ay=2\"
\n" ); document.write( " \"-5%2Ax%2B7%2Ay=0\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"-1%2Ax%2B3%2Ay=2\" (red) \"-5%2Ax%2B7%2Ay=0\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"7%2F4\",\"5%2F4\"). This verifies our answer.

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