document.write( "Question 1177516: A rectangular lawn measures 8 m by 4 m and is surrounded by a flowerbed of
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document.write( "uniform width. The combined area of the lawn and flowerbed is 6 more than
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document.write( "triple the area of the lawn alone. What is the width of the flowerbed? \n" );
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Algebra.Com's Answer #806558 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Lawn with area of 32m^2 \n" ); document.write( "Combined area is 96 m^2. \n" ); document.write( "the length of the combined area is 8 m +2 x m \n" ); document.write( "the width is 4 m+2 x m \n" ); document.write( "the area of the combined is 32+24x+4x^2=102 \n" ); document.write( "so 4x^2+24x-70=0 \n" ); document.write( "2x^2+12x-35=0 \n" ); document.write( "x=(1/4)(-12 +/- sqrt (144+280)); sqrt 424=20.59 \n" ); document.write( "positive root is 2.15 m the width \n" ); document.write( "- \n" ); document.write( "dimensions are 12.3m x 8.3m=102.09 m (rounding error) \n" ); document.write( " |