document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=705076>Question 705076</A>: <I><SPAN STYLE=\"word-break: break-all;\"> square poster has sides measuring 2ft less than the sides of a square sign.  If the difference between their areas is 52 sq ft find the length of the sides of the poster & sign.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806542 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sign side length: x<BR>\n" );
document.write( "poster side length: x-2\r<BR>\n" );
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document.write( "x^2 - (x-2)^2 = 52<BR>\n" );
document.write( "x^2 - (x^2 - 4x + 4) = 52<BR>\n" );
document.write( "4x - 4 = 52<BR>\n" );
document.write( "4x = 56<BR>\n" );
document.write( "x = 14\r<BR>\n" );
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document.write( "sign side length = 14 ft<BR>\n" );
document.write( "poster side length = 12 ft </SPAN>\n" );
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