document.write( "Question 110680: y=1/3x + 2/3
\n" ); document.write( "y=5/7x-2 \n" ); document.write( "
Algebra.Com's Answer #80653 by stanbon(75887)\"\" \"About 
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y=1/3x + 2/3
\n" ); document.write( "y=5/7x - 2
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\n" ); document.write( "(1/3)x+(2/3) = (5/7)x-2
\n" ); document.write( "[(5/7)-(1/3)]x = (2/3)+2
\n" ); document.write( "(8/21)x = 8/3
\n" ); document.write( "x = (8/3)(21/8)
\n" ); document.write( "x = 7
\n" ); document.write( "-------------
\n" ); document.write( "Substitute into y = (1/3)x+(2/3) to solve for \"y\":
\n" ); document.write( "y = (1/3)*7+2/3 = 9/3 = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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