document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1177471>Question 1177471</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two points have coordinates A(2,3) and B(6,7).If C(7,t) lies on the perpendicular bisector of AB,find the value of t. Find the coordinates of D such that line AB is the perpendicular bisector of CD. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806521 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the equation of the line AB:slope is 4/4=1<BR>\n" );
document.write( "y-y1=m(x-x1), m slope (x1, y1) point<BR>\n" );
document.write( "so y-3=1(x-2)<BR>\n" );
document.write( "y=x+1<BR>\n" );
document.write( "-<BR>\n" );
document.write( "midpoint of AB is half way between x s and half way between y s or (4,5)<BR>\n" );
document.write( "so the equation of the line has slope -1 (negative reciprocal of 1 for perpendicular bisector) and the equation is y-5=-1(x-4)<BR>\n" );
document.write( "y=-x+9<BR>\n" );
document.write( "we are given that C has coordinates (7, t)<BR>\n" );
document.write( "so when x=7, y=2<BR>\n" );
document.write( "t=2<BR>\n" );
document.write( "I am not clear what D is, but C is (7, 2) and the two lines have the equations given above and the graph shows this below.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%2B1%2C-x%2B9%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%2B1%2C-x%2B9%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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