document.write( "Question 1177486: In parallelogram ABCD, AB=125cm, AD=132cm, and the length of diagonal AC is 37cm. The area of the parallelogram, in cm squared, is
\n" ); document.write( "a) 1155 b) 2310 c) 2442 d)4620 e)4884
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Algebra.Com's Answer #806494 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "Draw perpendicular AE from A to side CD.

\n" ); document.write( "Let CE=x so BE=132-x; let the length of AE be y.

\n" ); document.write( "Then right triangles AEC and AEB give us

\n" ); document.write( "\"x%5E2%2By%5E2+=+37%5E2\" [1]
\n" ); document.write( "\"%28132-x%29%5E2%2By%5E2+=+125%5E2\" [2]

\n" ); document.write( "Expand [2]:

\n" ); document.write( "\"132%5E2-264x%2Bx%5E2+=+125%5E2\" [3]

\n" ); document.write( "Subtract [1] from [3]:

\n" ); document.write( "\"132%5E2-264x+=+125%5E2-37%5E2\"

\n" ); document.write( "Use a calculator and basic algebra to find x; then use [1] to find y.

\n" ); document.write( "Then the area of the parallelogram is base times height, which is 132 times y.

\n" ); document.write( "One of the given answer choices is correct....

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