document.write( "Question 1177438: A fenced pasture has a central rectangular corral within it that measures 10m by 5m.
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document.write( "The total area of the fenced pasture (outside the corral) is 1008 m².
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document.write( " If the width of the pasture border on the long side is double the width of the pasture border on the short side, what is the width of the border?
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document.write( "Find the width of the pasture border on each side of the corral using factors.
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document.write( "Draw a labeled picture, use let statements and show your work.
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Algebra.Com's Answer #806452 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x be the width on the sides \n" ); document.write( "2x the width on the length\r \n" ); document.write( "\n" ); document.write( "(50+2x)(10+4x) -50=1008\r \n" ); document.write( "\n" ); document.write( "500 +200x +20x +8x^2-1058=0\r \n" ); document.write( "\n" ); document.write( "8x^2 +220x -558\r \n" ); document.write( "\n" ); document.write( "Solve for x we get x= 2.34 m \n" ); document.write( "width along side = 2.34 \n" ); document.write( "width along length = 2x = 4.68 m\r \n" ); document.write( "\n" ); document.write( "CHECK\r \n" ); document.write( "\n" ); document.write( "total length =2.34 *2 =4.68 +50 = 54.68\r \n" ); document.write( "\n" ); document.write( " total width =2.34 *4 = 9.36+10 = 19.36\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(54.68)(19.36)-1008 = 50.6 m^2 \n" ); document.write( " |