document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1177238>Question 1177238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Diameter  12.0 Frequency 5 , Diameter 13.0 Frequency 11 Diameter 14.0 Frequency 24 ,Diameter 20.0 Frequency  15 ,Diameter 25.0 Frequency  ,5?\r<BR>\n" );
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document.write( "How do you find the probability of each diameter? P(x)\r<BR>\n" );
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document.write( "thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806448 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806448\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Look at the relative frequencies<BR>\n" );
document.write( "There are 60 such diameters<BR>\n" );
document.write( "for diameter 12.0 there are 5, for a relative frequency of 5/60. That is the probability for diameter 12.<BR>\n" );
document.write( "Similarly, <BR>\n" );
document.write( "for 13.0 the RF is 11/60<BR>\n" );
document.write( "for 14.0 the RF is 24.60 or 0.4<BR>\n" );
document.write( "for 20.0 the RF is 15/60 or 0.25<BR>\n" );
document.write( "for 25.0 the RF is 5/60<BR>\n" );
document.write( "The relative frequencies add up to 1, and they must. </SPAN>\n" );
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