document.write( "Question 1177440: The perimeter of a rectangle is 16 feet. If twice its length is 4 times its width, find the width and the length of a rectangle.\r
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document.write( "My Work:
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document.write( "Equation 1: 2L=4W
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document.write( "Equation 2: L+W=16\r
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document.write( "W=16/3
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document.write( "L=10/6 \n" );
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Algebra.Com's Answer #806445 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The perimeter of a rectangle: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the perimeter of a rectangle is \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if twice its length is \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "go to\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "the width is \n" ); document.write( " \n" ); document.write( " |