document.write( "Question 727779: find three positive consecutive odd integers such that the square of the smallest is 9 more than the sum of the other two
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Algebra.Com's Answer #806417 by CubeyThePenguin(3113)\"\" \"About 
You can put this solution on YOUR website!
consecutive positive odd integers: (x-2), x, (x+2)\r
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\n" ); document.write( "\n" ); document.write( "(x-2)^2 = 9 + x + (x+2)
\n" ); document.write( "x^2 - 4x + 4 = 2x + 11
\n" ); document.write( "x^2 - 6x - 7 = 0
\n" ); document.write( "(x - 7)(x + 1) = 0
\n" ); document.write( "x = 7, x = -1\r
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\n" ); document.write( "\n" ); document.write( "integers are positive ----> integers are 5, 7, 9
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