document.write( "Question 727779: find three positive consecutive odd integers such that the square of the smallest is 9 more than the sum of the other two
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Algebra.Com's Answer #806417 by CubeyThePenguin(3113) You can put this solution on YOUR website! consecutive positive odd integers: (x-2), x, (x+2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-2)^2 = 9 + x + (x+2) \n" ); document.write( "x^2 - 4x + 4 = 2x + 11 \n" ); document.write( "x^2 - 6x - 7 = 0 \n" ); document.write( "(x - 7)(x + 1) = 0 \n" ); document.write( "x = 7, x = -1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "integers are positive ----> integers are 5, 7, 9 \n" ); document.write( " |