document.write( "Question 110682: In coloradoCreek, Darrell can row 24 km down stream in 6 hours or he can row 18 km upstream in the same amount of time. Find the rate he rows in still water and the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #80638 by Earlsdon(6294)\"\" \"About 
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Let R = Darrell's rowing speed in still waters and C = The current speed.
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\n" ); document.write( "From the the problem description, you can write:
\n" ); document.write( "1) \"d%5B1%5D+=+r%5B1%5Dt%5B1%5D\" For the downstream trip.
\n" ); document.write( "2) \"d%5B2%5D+=+r%5B2%5Dt%5B2%5D\" For the upstream trip.\r
\n" ); document.write( "\n" ); document.write( "1) \"24+=+r%5B1%5D%286%29\"
\n" ); document.write( "\"r%5B1%5D+=+4\"
\n" ); document.write( "2) \"18+=+r%5B2%5D%286%29\"
\n" ); document.write( "\"r%5B2%5D+=+3\"\r
\n" ); document.write( "\n" ); document.write( "The downstream trip rate can be thought of as Darrells's rowing speed plus the current speed, or:
\n" ); document.write( "\"r%5B1%5D+=+R%2BC\" or:
\n" ); document.write( "\"4+=+R%2BC\"
\n" ); document.write( "The upstream trip rate can be thought of as Darrell's rowing speed minus the current speed, or:
\n" ); document.write( "\"r%5B2%5D+=+R-C\" or:
\n" ); document.write( "\"3+=+R-C\"
\n" ); document.write( "So you can add these two equations to find the value of R, Darrell's rowing speed in still water:\r
\n" ); document.write( "\n" ); document.write( "\"4+=+R%2BC\"
\n" ); document.write( "\"3+=+R-C\"
\n" ); document.write( "-------------
\n" ); document.write( "\"2R+=+7\"
\n" ); document.write( "\"R+=+3.5\"
\n" ); document.write( "Darrell's rowing speed in still water is 3.5 km/hr.
\n" ); document.write( "The current speed is:
\n" ); document.write( "\"C+=+R-3\"
\n" ); document.write( "\"C+=+3.5-3\"
\n" ); document.write( "\"C+=+0.5\"km/hr
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