document.write( "Question 1177422: A survey reports it results by starting that standard error of the mean to be is 20.
\n" ); document.write( "The population standard deviation is 500.
\n" ); document.write( "1:How large is the sample used in this surveying?
\n" ); document.write( "2: What is the probability that the sample mean will be within 25 of the population mean?
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Algebra.Com's Answer #806377 by Theo(13342)\"\" \"About 
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standard error is equal to population standard deviation divided by square root of sample size.\r
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\n" ); document.write( "\n" ); document.write( "the formula is s = psd / sqrt(ss).\r
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\n" ); document.write( "\n" ); document.write( "s is the standard error.
\n" ); document.write( "psd is population standard deviation.
\n" ); document.write( "ss is sample size.\r
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\n" ); document.write( "\n" ); document.write( "when s = 20 and psd = 500, the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "20 = 500 / sqrt(ss)\r
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\n" ); document.write( "\n" ); document.write( "solve for sqrt(ss) to get:\r
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\n" ); document.write( "\n" ); document.write( "sqrt(ss) = 500 / 20 = 25\r
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\n" ); document.write( "\n" ); document.write( "solve for ss to get:\r
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\n" ); document.write( "\n" ); document.write( "ss = 25^2 = 625\r
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\n" ); document.write( "\n" ); document.write( "that's the sample size.\r
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\n" ); document.write( "\n" ); document.write( "the formula for z-score is:\r
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\n" ); document.write( "\n" ); document.write( "z = (x - m) / s\r
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\n" ); document.write( "\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the raw mean
\n" ); document.write( "s is the standard error.\r
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\n" ); document.write( "\n" ); document.write( "when (x - m) = 25, and s = 20, the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "z = 25 / 20 = 1.25\r
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\n" ); document.write( "\n" ); document.write( "since the normal distribution curve is symmetric bout the mean, then the confidence interval is z-score of -1.25 to 1.25.\r
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\n" ); document.write( "\n" ); document.write( "the probability is the area under the normal distribution curve between those 2 z-scores.\r
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\n" ); document.write( "\n" ); document.write( "that probability is .7887003221.\r
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\n" ); document.write( "\n" ); document.write( "the probability that the sample mean will be within 25 of the population mean is .7887003221.\r
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\n" ); document.write( "\n" ); document.write( "this works regardless of the mean.\r
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\n" ); document.write( "\n" ); document.write( "for example:\r
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\n" ); document.write( "\n" ); document.write( "assume the mean is 1500.\r
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\n" ); document.write( "\n" ); document.write( "the z-score formula becomes plus or minus 1.25 = (x - 1500) / 20\r
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\n" ); document.write( "\n" ); document.write( "solve for the raw score to get:\r
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\n" ); document.write( "\n" ); document.write( "on the high side, x = 20 * 1.25 + 1500
\n" ); document.write( "on the low side, x = 20 * -1.25 + 1500\r
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\n" ); document.write( "\n" ); document.write( "since 20 * 1.25 is always equal to 25, then you get:\r
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\n" ); document.write( "\n" ); document.write( "x = 1500 - 25 or x = 1500 + 25.\r
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\n" ); document.write( "\n" ); document.write( "the sample mean will always be within 25 of the population mean if the z-score is plus or minus 1.25 and the standard error is 20, regardless of what the mean is.\r
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\n" ); document.write( "\n" ); document.write( "standard error = psd / sqrt(ss)
\n" ); document.write( "with a sample size of 625 and a psd of 500, this becomes:
\n" ); document.write( "standard error = 500 / sqrt(625) = = 500 / 25 = 20
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