document.write( "Question 791444: Find three consecutive integers such that five times the third integer equals twice the first integer plus seven more than the second integer? \n" ); document.write( "
Algebra.Com's Answer #806349 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Oh, my........

\n" ); document.write( "Tutor @CubeyThePenguin: wrong equation, leading to wrong answer.

\n" ); document.write( "Tutor @MathTherapy: nothing of use to you the student....

\n" ); document.write( "Tutor @josgarithmetic: algebra errors, leading to wrong answer... (which she could have seen if she had bothered to check to see if her answers were right).

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\n" ); document.write( "While there are many problems involving three consecutive integers where it is advantageous to call the numbers x-1, x, and x+1, I don't see that being helpful here. So let the numbers be x, x+1, and x+2. Then

\n" ); document.write( "\"...five times the third integer equals twice the first integer plus seven more than the second integer\"

\n" ); document.write( "5 times the third integer: 5(x+2)

\n" ); document.write( "twice the first integer plus 7 more than the second integer: 2x+((x+1)+7)

\n" ); document.write( "\"5%28x%2B2%29+=+2x%2B%28%28x%2B1%29%2B7%29\"
\n" ); document.write( "\"5x%2B10+=+3x%2B8\"
\n" ); document.write( "\"2x+=+-2\"
\n" ); document.write( "\"x+=+-1\"

\n" ); document.write( "ANSWER: The three consecutive integers are -1, 0, and 1.

\n" ); document.write( "CHECK:
\n" ); document.write( "5 times the third integer: 5(1) = 5

\n" ); document.write( "twice the first integer plus 7 more than the second integer: 2(-1)+(0+7) = -2+7 = 5
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