document.write( "Question 791444: Find three consecutive integers such that five times the third integer equals twice the first integer plus seven more than the second integer? \n" ); document.write( "
Algebra.Com's Answer #806349 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Oh, my........ \n" ); document.write( "Tutor @CubeyThePenguin: wrong equation, leading to wrong answer. \n" ); document.write( "Tutor @MathTherapy: nothing of use to you the student.... \n" ); document.write( "Tutor @josgarithmetic: algebra errors, leading to wrong answer... (which she could have seen if she had bothered to check to see if her answers were right). \n" ); document.write( "------------------------------------------------------ \n" ); document.write( "While there are many problems involving three consecutive integers where it is advantageous to call the numbers x-1, x, and x+1, I don't see that being helpful here. So let the numbers be x, x+1, and x+2. Then \n" ); document.write( "\"...five times the third integer equals twice the first integer plus seven more than the second integer\" \n" ); document.write( "5 times the third integer: 5(x+2) \n" ); document.write( "twice the first integer plus 7 more than the second integer: 2x+((x+1)+7) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: The three consecutive integers are -1, 0, and 1. \n" ); document.write( "CHECK: \n" ); document.write( "5 times the third integer: 5(1) = 5 \n" ); document.write( "twice the first integer plus 7 more than the second integer: 2(-1)+(0+7) = -2+7 = 5 \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |