document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=757854>Question 757854</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5 consecutive positive integer are such that twice the product of the smallest and largest integers exceeds the square of the middle integer by 41. By letting x equal the smallest integer, set up and solve a quadratic equation to find the middle integer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806271 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806271\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consecutive positive integers: x, (x+1), (x+2), (x+3), (x+4)\r<BR>\n" );
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document.write( "2(x)(x+4) = (x+2)^2 + 41<BR>\n" );
document.write( "2(x^2 + 4x) = x^2 + 4x + 4 + 41<BR>\n" );
document.write( "2x^2 + 8x = x^2 + 4x + 45<BR>\n" );
document.write( "x^2 + 4x - 45 = 0<BR>\n" );
document.write( "(x + 9)(x - 5) = 0<BR>\n" );
document.write( "x = -9, x = 5\r<BR>\n" );
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document.write( "x has to be positive, so the middle integer is x + 2 = 7. </SPAN>\n" );
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