document.write( "Question 1177337: When a plane flies with the wind, it can travel 920 miles in 2 hours. When the plane flies in the opposite direction, against the wind, it takes 4 hours to fly the same distance. Find the rate of the plane in still air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #806220 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "let the rate of the plane in still air be x\r \n" ); document.write( "\n" ); document.write( "and the rate of the wind be y\r \n" ); document.write( "\n" ); document.write( "rate with wind =( x+y) mph\r \n" ); document.write( "\n" ); document.write( "distance = 920 miles\r \n" ); document.write( "\n" ); document.write( "time = 2 hours\r \n" ); document.write( "\n" ); document.write( "d/r = t \n" ); document.write( "920/(x+y) =2\r \n" ); document.write( "\n" ); document.write( "2x+2y =920 \n" ); document.write( "/2 \n" ); document.write( "x+y = 460 --------------(1)\r \n" ); document.write( "\n" ); document.write( "Against wind rate = (x-y)\r \n" ); document.write( "\n" ); document.write( "920/(x-y) = 4\r \n" ); document.write( "\n" ); document.write( "4x-4y = 920 \n" ); document.write( "/4 \n" ); document.write( "x-y = 230------------------(2)\r \n" ); document.write( "\n" ); document.write( "Add equation (1) & (2)\r \n" ); document.write( "\n" ); document.write( "2x = 690 \n" ); document.write( "x= 345 \n" ); document.write( "the rate of the plane in still air 345 mph\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the rate of the wind be 115 mph \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |