document.write( "Question 1177337: When a plane flies with the​ wind, it can travel 920 miles in 2 hours. When the plane flies in the opposite​ direction, against the​ wind, it takes 4 hours to fly the same distance. Find the rate of the plane in still air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #806220 by mananth(16946)\"\" \"About 
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\n" ); document.write( "let the rate of the plane in still air be x\r
\n" ); document.write( "\n" ); document.write( "and the rate of the wind be y\r
\n" ); document.write( "\n" ); document.write( "rate with wind =( x+y) mph\r
\n" ); document.write( "\n" ); document.write( "distance = 920 miles\r
\n" ); document.write( "\n" ); document.write( "time = 2 hours\r
\n" ); document.write( "\n" ); document.write( "d/r = t
\n" ); document.write( "920/(x+y) =2\r
\n" ); document.write( "\n" ); document.write( "2x+2y =920
\n" ); document.write( "/2
\n" ); document.write( "x+y = 460 --------------(1)\r
\n" ); document.write( "\n" ); document.write( "Against wind rate = (x-y)\r
\n" ); document.write( "\n" ); document.write( "920/(x-y) = 4\r
\n" ); document.write( "\n" ); document.write( "4x-4y = 920
\n" ); document.write( "/4
\n" ); document.write( "x-y = 230------------------(2)\r
\n" ); document.write( "\n" ); document.write( "Add equation (1) & (2)\r
\n" ); document.write( "\n" ); document.write( "2x = 690
\n" ); document.write( "x= 345
\n" ); document.write( "the rate of the plane in still air 345 mph\r
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\n" ); document.write( "\n" ); document.write( "the rate of the wind be 115 mph \r
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