document.write( "Question 812194: You must form an equation and solve it to the remaining application problems. Oh, and don't forget to clearly define your variable(s). Please write your answers in complete sentences.\r
\n" ); document.write( "\n" ); document.write( "A rectangular mirror has an area of 10 FT^2 (square), and it is 1.5 ft longer than it is wide. Find the dimensions of the mirror.\r
\n" ); document.write( "\n" ); document.write( "A=(L)(W), so
\n" ); document.write( "10=W+
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Algebra.Com's Answer #806210 by CubeyThePenguin(3113)\"\" \"About 
You can put this solution on YOUR website!
w = width\r
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\n" ); document.write( "\n" ); document.write( "area = (length)(width)
\n" ); document.write( "10 = (w)(w + 1.5)
\n" ); document.write( "10 = w^2 + 1.5w
\n" ); document.write( "20 = 2w^2 + 3w
\n" ); document.write( "0 = 2w^2 + 3w - 20
\n" ); document.write( "0 = (2w - 5)(w + 4)
\n" ); document.write( "w = 5/2, w = -4\r
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\n" ); document.write( "\n" ); document.write( "Distance has to be positive, so the mirror is 5/2 = 2.5 ft wide and 4 ft long.
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