document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=859388>Question 859388</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I break this down:<BR>\n" );
document.write( "Two consecutive negative integers are multiplied together. To this product is added the sum of the integer. If the result equals 41, determine the integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806208 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806208\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = smallest integer\r<BR>\n" );
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document.write( "x(x+1) + (x + (x+1)) = 41<BR>\n" );
document.write( "x^2 + x + 2x + 1 = 41<BR>\n" );
document.write( "x^2 + 3x - 40 = 0<BR>\n" );
document.write( "(x + 8)(x - 5) = 0<BR>\n" );
document.write( "x = -8, x = 5\r<BR>\n" );
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document.write( "x is negative, so the integers are -8 and -7. </SPAN>\n" );
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