document.write( "Question 784900: find three consecutive integers such that the product of 5 and the sum of the first two was 7 greater than the opposite of the third. \n" ); document.write( "
Algebra.Com's Answer #806198 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! consecutive integers: (x-1), x, (x+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5((x-1) + x) = 7 - (x + 1) \n" ); document.write( "5(2x - 1) = 7 - x - 1 \n" ); document.write( "10x - 5 = -x + 6 \n" ); document.write( "11x = 11 \n" ); document.write( "x = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The integers are 0, 1, and 2. \n" ); document.write( " |