document.write( "Question 1177321: Hi
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document.write( "If A gave 22 sweets to D she would have 4 times as many sweets as D . If D gave 18 sweets to A she would have 1/9 as many sweets as A and D.
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document.write( "How many sweets do they have altogether. \r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #806179 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! If A gave 22 sweets to D she would have 4 times as many sweets as D. \n" ); document.write( "a - 22 = 4(d+22) \n" ); document.write( "a - 22 = 4d + 88 \n" ); document.write( "a - 4d = 22 + 88 \n" ); document.write( "a - 4d = 110 \n" ); document.write( " If D gave 18 sweets to A she would have 1/9 as many sweets as A and D. \n" ); document.write( "d - 18 = \n" ); document.write( "mult the eq by 9, cancel the denominator \n" ); document.write( "9d - 162 = a + d \n" ); document.write( "-a + 9d - d = 162 \n" ); document.write( "-a + 8d = 162 \n" ); document.write( ": \n" ); document.write( "Use these two equations for elimination \n" ); document.write( "a - 4d = 110 \n" ); document.write( "-a +8d = 162 \n" ); document.write( "-------------------addition eliminates a, find d \n" ); document.write( "0 + 4d = 272 \n" ); document.write( "d = 272/4 \n" ); document.write( "d = 68 sweets for D originally \n" ); document.write( "then \n" ); document.write( "a - 22 = 4(68+22) \n" ); document.write( "a = 4(90) + 22 \n" ); document.write( "a = 360 + 22 \n" ); document.write( "a = 382 sweets for A originally \n" ); document.write( ": \n" ); document.write( " How many sweets do they have altogether. \n" ); document.write( "382 + 68 = 450 \n" ); document.write( " \n" ); document.write( " |