document.write( "Question 791444: Find three consecutive integers such that five times the third integer equals twice the first integer plus seven more than the second integer? \n" ); document.write( "
Algebra.Com's Answer #806158 by CubeyThePenguin(3113)![]() ![]() You can put this solution on YOUR website! consecutive integers: (x-1), x, (x+1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5(x+1) = 2(x-1) + 7x \n" ); document.write( "5x + 5 = 9x - 2 \n" ); document.write( "7 = 4x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The solutions of this equation are not integers. \n" ); document.write( " |