document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=793158>Question 793158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two integers are consecutive positive integers. If you multiply the smaller integer with 3 times the larger it equals 36. Find the sum of the two integers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806155 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806155\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consecutive positive integers: x, (x+1)\r<BR>\n" );
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document.write( "3x(x+1) = 36<BR>\n" );
document.write( "x(x+1) = 12<BR>\n" );
document.write( "x^2 + x = 12<BR>\n" );
document.write( "x^2 + x - 12 = 0<BR>\n" );
document.write( "(x + 4)(x - 3) = 0<BR>\n" );
document.write( "x = -4, x = 3\r<BR>\n" );
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document.write( "x must be positive, so the integers are 3 and 4. </SPAN>\n" );
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