document.write( "Question 792830: Find three consecutive odd integers such that the sum of the squares of the first two is 15 less than the square of the third. \n" ); document.write( "
Algebra.Com's Answer #806144 by CubeyThePenguin(3113)\"\" \"About 
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consecutive odd integers: (x-2), x, (x+2)\r
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\n" ); document.write( "\n" ); document.write( "(x-2)^2 + x^2 = (x+2)^2 - 15
\n" ); document.write( "x^2 - 4x + 4 + x^2 = x^2 + 4x + 4 - 15
\n" ); document.write( "2x^2 - 4x + 4 = x^2 + 4x - 11
\n" ); document.write( "x^2 - 8x + 15 = 0
\n" ); document.write( "(x - 3)(x - 5) = 0\r
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\n" ); document.write( "\n" ); document.write( "The integers could be (1, 3, 5) or (3, 5, 7).
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