document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=850321>Question 850321</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this\r<BR>\n" );
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document.write( "Three consecutive odd positive integers are such that the squares of the first two integers is greater than the square of the third by 65. Find the integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806132 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> consecutive odd integers: (x-2), x, (x+2)\r<BR>\n" );
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document.write( "(x-2)^2 + x^2 = (x+2)^2 + 65<BR>\n" );
document.write( "x^2 - 4x + 4 + x^2 = x^2 + 4x + 4 + 65<BR>\n" );
document.write( "2x^2 - 4x + 4 = x^2 + 4x + 69<BR>\n" );
document.write( "x^2 - 8x - 65 = 0<BR>\n" );
document.write( "(x - 13)(x + 5) = 0<BR>\n" );
document.write( "x = 13, x = -5\r<BR>\n" );
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document.write( "x is positive, so the integers are 11, 13, and 15. </SPAN>\n" );
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