document.write( "Question 1177286: Please help me solve this problem : \r
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\n" ); document.write( "\n" ); document.write( " p(x) = k /(x + 1), x = 1, 2, 3, 4\r
\n" ); document.write( "\n" ); document.write( "is a probability function. Graph the density and cumulative distribution functions.\r
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Algebra.Com's Answer #806126 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"p%28x%29+=+k%2F%28x+%2B+1%29\", x = 1, 2, 3, 4\r\n" );
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document.write( "the sum of the values must be 1.\r\n" );
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document.write( "\"k%2F2%2Bk%2F3%2Bk%2F4%2Bk%2F5=1\"\r\n" );
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document.write( "Multiply by LCM = 60\r\n" );
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document.write( "\"60k%2F2%2B60k%2F3%2B60k%2F4%2B60k%2F5=60\"\r\n" );
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document.write( "\"30k%2B20k%2B15k%2B12k=60\"\r\n" );
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document.write( "\"77k=60\"\r\n" );
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document.write( "\"k=60%2F77\"\r\n" );
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document.write( "\"p%28x%29+=+k%2F%28x+%2B+1%29\"\r\n" );
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document.write( "\"p%28x%29+=+%2860%2F77%29%2F%28x+%2B+1%5E%22%22%29\"\r\n" );
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document.write( "Multiply top and bottom by 77\r\n" );
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document.write( "\"p%28x%29+=+60%2F%2877%28x+%2B+1%29%29\"\r\n" );
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document.write( "\"p%281%29+=+60%2F%2877%281+%2B+1%29%29=60%2F%28%2877%29%282%29%29=30%2F77\"\r\n" );
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document.write( "\"p%282%29+=+60%2F%2877%282+%2B+1%29%29=60%2F%28%2877%29%283%29%29=20%2F77\"\r\n" );
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document.write( "\"p%283%29+=+60%2F%2877%283+%2B+1%29%29=60%2F%28%2877%29%284%29%29=15%2F77\"\r\n" );
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document.write( "\"p%284%29+=+60%2F%2877%284+%2B+1%29%29=60%2F%28%2877%29%285%29%29=12%2F77\"\r\n" );
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document.write( "Graph of probability function \r\n" );
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document.write( "\"p%28x%29+=+60%2F%2877%28x+%2B+1%29%29\" x = 1, 2, 3, 4\r\n" );
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document.write( "To get the the cumulative distribution function: \r\n" );
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document.write( "\"c%281%29+=+p%281%29+=+30%2F77\"\r\n" );
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document.write( "\"c%282%29+=+P%281%29%2Bp%282%29+=30%2F77%2B20%2F77=50%2F77\"\r\n" );
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document.write( "\"c%283%29+=+P%281%29%2Bp%282%29%2Bp%283%29+=30%2F77%2B20%2F77%2B15%2F77=65%2F77\" \r\n" );
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document.write( "Here's the graph of the cumulative distribution function which accumulates\r\n" );
document.write( "as it goes:\r\n" );
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document.write( "Edwin
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