document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=860783>Question 860783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is 25 km long the length of one leg is 17 km less than the other find the length of the legs </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #806096 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=806096\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 + (x + 17)^2 = 25^2<BR>\n" );
document.write( "x^2 + x^2 + 34x + 289 = 625<BR>\n" );
document.write( "2x^2 + 34x - 336 = 0<BR>\n" );
document.write( "x^2 + 17x - 168 = 0<BR>\n" );
document.write( "(x + 24)(x - 7) = 0<BR>\n" );
document.write( "x = -24, x = 7\r<BR>\n" );
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document.write( "x has to be positive, so the shorter leg is 7 km and the longer leg is 24 km.\r<BR>\n" );
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document.write( "Alternatively, remember that 7, 24, and 25 make up a Pythagorean triple. </SPAN>\n" );
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